b^2=256b=

Solution for b^2=256b= equation:

b^2=256b=

We move all terms to the left:

b^2-(256b)=0

a = 1; b = -256; c = 0;
Δ = b2-4ac
Δ = -2562-4·1·0
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65536}=256$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-256)-256}{2*1}=\frac{0}{2}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-256)+256}{2*1}=\frac{512}{2}
=256
$